Day 22 of 100 days of code
On the 22nd day, I took on three practice problems on CodeChef. Here they are:
#include <bits/stdc++.h>
using namespace std;
bool solution(int a,int b,int c,int d,int e){
return ((a+b)<=d && c<=e);
}
int main(){
int t;
cin>>t;
while(t--){
int a,b,c,d,e;
cin>>a>>b>>c>>d>>e;
if(solution(a,b,c,d,e)||solution(a,c,b,d,e)||solution(b,c,a,d,e)){
cout<<"YES"<<endl;
}else{
cout<<"NO"<<endl;
}
}
}
#include <bits/stdc++.h>
using namespace std;
int solution(string s){
int count_0 = count(s.begin(),s.end(),'0');
int count_1 = count(s.begin(),s.end(),'1');
if(count_0>=count_1){
return count_1;
}
return 1+count_0;
}
int main(){
int t;
cin>>t;
while(t--){
int n;
cin>>n;
string s;
cin>>s;
int ans = solution(s);
cout<<ans<<endl;
}
}
#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
int solution(int arr[],int n){
int cnt = n;
for(int i =0;i<n-1;i++){
ll sum = arr[i];
ll p = arr[i];
for(int j =i+1;j<n;j++){
sum += arr[j];
p *= arr[j];
if(sum==p){
cnt++;
}
}
}
return cnt;
}
int main(){
int t;
cin>>t;
while(t--){
int n;
cin>>n;
int arr[n];
for(int i =0;i<n;i++){
cin>>arr[i];
}
int ans =solution(arr,n);
cout<<ans<<endl;
}
}
Tomorrow, I plan to delve into sliding window algorithms and related problems. Join me in tomorrow's blog for more insights.
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